Question on: JAMB Mathematics - 2009
The distance travelled by a particle from a fixed point is given as s = (t3 - t2 - t + 5)cm. Find the minimum distance that the particle can cover from the fixed point.
A
2.3 cm
B
4.0cm
C
5.2
D
g
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Correct Option: B
S = (t3 - t2 - t + 5)cm
\(\frac{ds}{dt}\) = 3t2 - 2t - 1
= (3t + 1)(t - 1)
t = -\(\frac{1}{3}\) or t = 1
Substitute value of t
s = (13 - 12 - 1 + 5)cm
= 4.0 cm
\(\frac{ds}{dt}\) = 3t2 - 2t - 1
= (3t + 1)(t - 1)
t = -\(\frac{1}{3}\) or t = 1
Substitute value of t
s = (13 - 12 - 1 + 5)cm
= 4.0 cm
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